Integral of $$$\frac{\cos{\left(x \right)}}{17 \sin{\left(2 x \right)}}$$$
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Find $$$\int \frac{\cos{\left(x \right)}}{17 \sin{\left(2 x \right)}}\, dx$$$.
Solution
Rewrite the integrand:
$${\color{red}{\int{\frac{\cos{\left(x \right)}}{17 \sin{\left(2 x \right)}} d x}}} = {\color{red}{\int{\frac{1}{34 \sin{\left(x \right)}} d x}}}$$
Rewrite the sine using the double angle formula $$$\sin\left(x\right)=2\sin\left(\frac{x}{2}\right)\cos\left(\frac{x}{2}\right)$$$:
$${\color{red}{\int{\frac{1}{34 \sin{\left(x \right)}} d x}}} = {\color{red}{\int{\frac{1}{68 \sin{\left(\frac{x}{2} \right)} \cos{\left(\frac{x}{2} \right)}} d x}}}$$
Multiply the numerator and denominator by $$$\sec^2\left(\frac{x}{2} \right)$$$:
$${\color{red}{\int{\frac{1}{68 \sin{\left(\frac{x}{2} \right)} \cos{\left(\frac{x}{2} \right)}} d x}}} = {\color{red}{\int{\frac{\sec^{2}{\left(\frac{x}{2} \right)}}{68 \tan{\left(\frac{x}{2} \right)}} d x}}}$$
Let $$$u=\tan{\left(\frac{x}{2} \right)}$$$.
Then $$$du=\left(\tan{\left(\frac{x}{2} \right)}\right)^{\prime }dx = \frac{\sec^{2}{\left(\frac{x}{2} \right)}}{2} dx$$$ (steps can be seen »), and we have that $$$\sec^{2}{\left(\frac{x}{2} \right)} dx = 2 du$$$.
The integral can be rewritten as
$${\color{red}{\int{\frac{\sec^{2}{\left(\frac{x}{2} \right)}}{68 \tan{\left(\frac{x}{2} \right)}} d x}}} = {\color{red}{\int{\frac{1}{34 u} d u}}}$$
Apply the constant multiple rule $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ with $$$c=\frac{1}{34}$$$ and $$$f{\left(u \right)} = \frac{1}{u}$$$:
$${\color{red}{\int{\frac{1}{34 u} d u}}} = {\color{red}{\left(\frac{\int{\frac{1}{u} d u}}{34}\right)}}$$
The integral of $$$\frac{1}{u}$$$ is $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:
$$\frac{{\color{red}{\int{\frac{1}{u} d u}}}}{34} = \frac{{\color{red}{\ln{\left(\left|{u}\right| \right)}}}}{34}$$
Recall that $$$u=\tan{\left(\frac{x}{2} \right)}$$$:
$$\frac{\ln{\left(\left|{{\color{red}{u}}}\right| \right)}}{34} = \frac{\ln{\left(\left|{{\color{red}{\tan{\left(\frac{x}{2} \right)}}}}\right| \right)}}{34}$$
Therefore,
$$\int{\frac{\cos{\left(x \right)}}{17 \sin{\left(2 x \right)}} d x} = \frac{\ln{\left(\left|{\tan{\left(\frac{x}{2} \right)}}\right| \right)}}{34}$$
Add the constant of integration:
$$\int{\frac{\cos{\left(x \right)}}{17 \sin{\left(2 x \right)}} d x} = \frac{\ln{\left(\left|{\tan{\left(\frac{x}{2} \right)}}\right| \right)}}{34}+C$$
Answer
$$$\int \frac{\cos{\left(x \right)}}{17 \sin{\left(2 x \right)}}\, dx = \frac{\ln\left(\left|{\tan{\left(\frac{x}{2} \right)}}\right|\right)}{34} + C$$$A