Integral of $$$x^{3}$$$
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Your Input
Find $$$\int x^{3}\, dx$$$.
Solution
Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=3$$$:
$${\color{red}{\int{x^{3} d x}}}={\color{red}{\frac{x^{1 + 3}}{1 + 3}}}={\color{red}{\left(\frac{x^{4}}{4}\right)}}$$
Therefore,
$$\int{x^{3} d x} = \frac{x^{4}}{4}$$
Add the constant of integration:
$$\int{x^{3} d x} = \frac{x^{4}}{4}+C$$
Answer
$$$\int x^{3}\, dx = \frac{x^{4}}{4} + C$$$A
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