Identify the conic section $$$y = x^{2} e^{4} + 1$$$
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Identify and find the properties of the conic section $$$y = x^{2} e^{4} + 1$$$.
Solution
The general equation of a conic section is $$$A x^{2} + B x y + C y^{2} + D x + E y + F = 0$$$.
In our case, $$$A = e^{4}$$$, $$$B = 0$$$, $$$C = 0$$$, $$$D = 0$$$, $$$E = -1$$$, $$$F = 1$$$.
The discriminant of the conic section is $$$\Delta = 4 A C F - A E^{2} - B^{2} F + B D E - C D^{2} = - e^{4}$$$.
Next, $$$B^{2} - 4 A C = 0$$$.
Since $$$B^{2} - 4 A C = 0$$$, the equation represents a parabola.
To find its properties, use the parabola calculator.
Answer
$$$y = x^{2} e^{4} + 1$$$A represents a parabola.
General form: $$$x^{2} e^{4} - y + 1 = 0$$$A.
Graph: see the graphing calculator.