Identify the conic section $$$- y^{2} = 0$$$
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Identify and find the properties of the conic section $$$- y^{2} = 0$$$.
Solution
The general equation of a conic section is $$$A x^{2} + B x y + C y^{2} + D x + E y + F = 0$$$.
In our case, $$$A = 0$$$, $$$B = 0$$$, $$$C = 1$$$, $$$D = 0$$$, $$$E = 0$$$, $$$F = 0$$$.
The discriminant of the conic section is $$$\Delta = 4 A C F - A E^{2} - B^{2} F + B D E - C D^{2} = 0$$$.
Next, $$$B^{2} - 4 A C = 0$$$.
Since $$$\Delta = 0$$$, this is the degenerated conic section.
Since $$$B^{2} - 4 A C = 0$$$, the equation represents a line.
Answer
$$$- y^{2} = 0$$$A represents the line $$$y = 0$$$A.
General form: $$$y^{2} = 0$$$A.
Factored form: $$$y^{2} = 0$$$A.
Graph: see the graphing calculator.