Identify the conic section $$$x = 3 y^{2} + 2 y + 2$$$

The calculator will identify and find the properties of the conic section $$$x = 3 y^{2} + 2 y + 2$$$, with steps shown.

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Your Input

Identify and find the properties of the conic section $$$x = 3 y^{2} + 2 y + 2$$$.

Solution

The general equation of a conic section is $$$A x^{2} + B x y + C y^{2} + D x + E y + F = 0$$$.

In our case, $$$A = 0$$$, $$$B = 0$$$, $$$C = 3$$$, $$$D = -1$$$, $$$E = 2$$$, $$$F = 2$$$.

The discriminant of the conic section is $$$\Delta = 4 A C F - A E^{2} - B^{2} F + B D E - C D^{2} = -3$$$.

Next, $$$B^{2} - 4 A C = 0$$$.

Since $$$B^{2} - 4 A C = 0$$$, the equation represents a parabola.

To find its properties, use the parabola calculator.

Answer

$$$x = 3 y^{2} + 2 y + 2$$$A represents a parabola.

General form: $$$- x + 3 y^{2} + 2 y + 2 = 0$$$A.

Graph: see the graphing calculator.


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