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Identify the conic section $$$x^{2} + y^{2} = 1$$$
Related calculators: Parabola Calculator, Circle Calculator, Ellipse Calculator, Hyperbola Calculator
Your Input
Identify and find the properties of the conic section $$$x^{2} + y^{2} = 1$$$.
Solution
The general equation of a conic section is $$$A x^{2} + B x y + C y^{2} + D x + E y + F = 0$$$.
In our case, $$$A = 1$$$, $$$B = 0$$$, $$$C = 1$$$, $$$D = 0$$$, $$$E = 0$$$, $$$F = -1$$$.
The discriminant of the conic section is $$$\Delta = 4 A C F - A E^{2} - B^{2} F + B D E - C D^{2} = -4$$$.
Next, $$$B^{2} - 4 A C = -4$$$.
Since $$$B^{2} - 4 A C \lt 0$$$, the equation represents a circle.
To find its properties, use the circle calculator.
Answer
$$$x^{2} + y^{2} = 1$$$A represents a circle.
General form: $$$x^{2} + y^{2} - 1 = 0$$$A.
Graph: see the graphing calculator.