Identify the conic section $$$25 x^{2} = 169$$$

Identify and find the properties of the conic section $$$25 x^{2} = 169$$$.

The general equation of a conic section is $$$A x^{2} + B x y + C y^{2} + D x + E y + F = 0$$$.

In our case, $$$A = 25$$$, $$$B = 0$$$, $$$C = 0$$$, $$$D = 0$$$, $$$E = 0$$$, $$$F = -169$$$.

The discriminant of the conic section is $$$\Delta = 4 A C F - A E^{2} - B^{2} F + B D E - C D^{2} = 0$$$.

Next, $$$B^{2} - 4 A C = 0$$$.

Since $$$\Delta = 0$$$, this is the degenerated conic section.

Since $$$B^{2} - 4 A C = 0$$$, the equation represents two parallel lines.

$$$25 x^{2} = 169$$$A represents a pair of the lines $$$x = - \frac{13}{5}$$$, $$$x = \frac{13}{5}$$$A.

General form: $$$25 x^{2} - 169 = 0$$$A.

Factored form: $$$\left(5 x - 13\right) \left(5 x + 13\right) = 0$$$A.

Graph: see the graphing calculator.