Identify the conic section $$$- \frac{1}{5} = - 3 x^{2}$$$

Identify and find the properties of the conic section $$$- \frac{1}{5} = - 3 x^{2}$$$.

The general equation of a conic section is $$$A x^{2} + B x y + C y^{2} + D x + E y + F = 0$$$.

In our case, $$$A = 3$$$, $$$B = 0$$$, $$$C = 0$$$, $$$D = 0$$$, $$$E = 0$$$, $$$F = - \frac{1}{5}$$$.

The discriminant of the conic section is $$$\Delta = 4 A C F - A E^{2} - B^{2} F + B D E - C D^{2} = 0$$$.

Next, $$$B^{2} - 4 A C = 0$$$.

Since $$$\Delta = 0$$$, this is the degenerated conic section.

Since $$$B^{2} - 4 A C = 0$$$, the equation represents two parallel lines.

$$$- \frac{1}{5} = - 3 x^{2}$$$A represents a pair of the lines $$$x = - \frac{\sqrt{15}}{15}$$$, $$$x = \frac{\sqrt{15}}{15}$$$A.

General form: $$$3 x^{2} - \frac{1}{5} = 0$$$A.

Factored form: $$$\left(15 x - \sqrt{15}\right) \left(15 x + \sqrt{15}\right) = 0$$$A.

Graph: see the graphing calculator.