Integral of $$$e^{u}$$$
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Solution
The integral of the exponential function is $$$\int{e^{u} d u} = e^{u}$$$:
$${\color{red}{\int{e^{u} d u}}} = {\color{red}{e^{u}}}$$
Therefore,
$$\int{e^{u} d u} = e^{u}$$
Add the constant of integration:
$$\int{e^{u} d u} = e^{u}+C$$
Answer
$$$\int e^{u}\, du = e^{u} + C$$$A