Integral of $$$\frac{x}{4}$$$

Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{1}{4}$$$ and $$$f{\left(x \right)} = x$$$:

$${\color{red}{\int{\frac{x}{4} d x}}} = {\color{red}{\left(\frac{\int{x d x}}{4}\right)}}$$

Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=1$$$:

$$\frac{{\color{red}{\int{x d x}}}}{4}=\frac{{\color{red}{\frac{x^{1 + 1}}{1 + 1}}}}{4}=\frac{{\color{red}{\left(\frac{x^{2}}{2}\right)}}}{4}$$

Therefore,

$$\int{\frac{x}{4} d x} = \frac{x^{2}}{8}$$

Add the constant of integration:

$$\int{\frac{x}{4} d x} = \frac{x^{2}}{8}+C$$

Answer: $$$\int{\frac{x}{4} d x}=\frac{x^{2}}{8}+C$$$