$$$\left[\begin{array}{cc}3 & 2\\2 & 3\\2 & -2\end{array}\right]\cdot \left[\begin{array}{cc}\frac{17}{225} & - \frac{8}{225}\\- \frac{8}{225} & \frac{17}{225}\end{array}\right]$$$

$$$\left[\begin{array}{cc}3 & 2\\2 & 3\\2 & -2\end{array}\right]\cdot \left[\begin{array}{cc}\frac{17}{225} & - \frac{8}{225}\\- \frac{8}{225} & \frac{17}{225}\end{array}\right]$$$을(를) 계산하세요.

$$$\left[\begin{array}{cc}{\color{Peru}3} & {\color{Purple}2}\\{\color{Chartreuse}2} & {\color{Fuchsia}3}\\{\color{Chocolate}2} & {\color{Crimson}-2}\end{array}\right]\cdot \left[\begin{array}{cc}{\color{Red}\frac{17}{225}} & {\color{DarkCyan}- \frac{8}{225}}\\{\color{GoldenRod}- \frac{8}{225}} & {\color{Chartreuse}\frac{17}{225}}\end{array}\right] = \left[\begin{array}{cc}{\color{Peru}\left(3\right)}\cdot {\color{Red}\left(\frac{17}{225}\right)} + {\color{Purple}\left(2\right)}\cdot {\color{GoldenRod}\left(- \frac{8}{225}\right)} & {\color{Peru}\left(3\right)}\cdot {\color{DarkCyan}\left(- \frac{8}{225}\right)} + {\color{Purple}\left(2\right)}\cdot {\color{Chartreuse}\left(\frac{17}{225}\right)}\\{\color{Chartreuse}\left(2\right)}\cdot {\color{Red}\left(\frac{17}{225}\right)} + {\color{Fuchsia}\left(3\right)}\cdot {\color{GoldenRod}\left(- \frac{8}{225}\right)} & {\color{Chartreuse}\left(2\right)}\cdot {\color{DarkCyan}\left(- \frac{8}{225}\right)} + {\color{Fuchsia}\left(3\right)}\cdot {\color{Chartreuse}\left(\frac{17}{225}\right)}\\{\color{Chocolate}\left(2\right)}\cdot {\color{Red}\left(\frac{17}{225}\right)} + {\color{Crimson}\left(-2\right)}\cdot {\color{GoldenRod}\left(- \frac{8}{225}\right)} & {\color{Chocolate}\left(2\right)}\cdot {\color{DarkCyan}\left(- \frac{8}{225}\right)} + {\color{Crimson}\left(-2\right)}\cdot {\color{Chartreuse}\left(\frac{17}{225}\right)}\end{array}\right] = \left[\begin{array}{cc}\frac{7}{45} & \frac{2}{45}\\\frac{2}{45} & \frac{7}{45}\\\frac{2}{9} & - \frac{2}{9}\end{array}\right]$$$

$$$\left[\begin{array}{cc}3 & 2\\2 & 3\\2 & -2\end{array}\right]\cdot \left[\begin{array}{cc}\frac{17}{225} & - \frac{8}{225}\\- \frac{8}{225} & \frac{17}{225}\end{array}\right] = \left[\begin{array}{cc}\frac{7}{45} & \frac{2}{45}\\\frac{2}{45} & \frac{7}{45}\\\frac{2}{9} & - \frac{2}{9}\end{array}\right]\approx \left[\begin{array}{cc}0.155555555555556 & 0.044444444444444\\0.044444444444444 & 0.155555555555556\\0.222222222222222 & -0.222222222222222\end{array}\right]$$$A