$$$- \frac{1}{x}$$$의 적분

$$$\int \left(- \frac{1}{x}\right)\, dx$$$을(를) 구하시오.

상수배 법칙 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$을 $$$c=-1$$$와 $$$f{\left(x \right)} = \frac{1}{x}$$$에 적용하세요:

$${\color{red}{\int{\left(- \frac{1}{x}\right)d x}}} = {\color{red}{\left(- \int{\frac{1}{x} d x}\right)}}$$

$$$\frac{1}{x}$$$의 적분은 $$$\int{\frac{1}{x} d x} = \ln{\left(\left|{x}\right| \right)}$$$:

$$- {\color{red}{\int{\frac{1}{x} d x}}} = - {\color{red}{\ln{\left(\left|{x}\right| \right)}}}$$

따라서,

$$\int{\left(- \frac{1}{x}\right)d x} = - \ln{\left(\left|{x}\right| \right)}$$

적분 상수를 추가하세요:

$$\int{\left(- \frac{1}{x}\right)d x} = - \ln{\left(\left|{x}\right| \right)}+C$$

$$$\int \left(- \frac{1}{x}\right)\, dx = - \ln\left(\left|{x}\right|\right) + C$$$A