Kalkulator Hukum Kosinus

Selesaikan segitiga, jika diketahui $$$a = 7$$$, $$$b = 14$$$, $$$C = 60^{\circ}$$$.

Menurut hukum kosinus: $$$c^{2} = a^{2} + b^{2} - 2 a b \cos{\left(C \right)}$$$.

Dalam kasus ini, $$$c^{2} = 7^{2} + 14^{2} - \left(2\right)\cdot \left(7\right)\cdot \left(14\right)\cdot \left(\cos{\left(60^{\circ} \right)}\right) = 147$$$.

Dengan demikian, $$$c = 7 \sqrt{3}$$$.

Menurut hukum kosinus: $$$a^{2} = b^{2} + c^{2} - 2 b c \cos{\left(A \right)}$$$.

Dalam kasus ini, $$$7^{2} = 14^{2} + \left(7 \sqrt{3}\right)^{2} - \left(2\right)\cdot \left(14\right)\cdot \left(7 \sqrt{3}\right)\cdot \left(\cos{\left(A \right)}\right)$$$.

Dengan demikian, $$$\cos{\left(A \right)} = \frac{\sqrt{3}}{2}$$$.

Dengan demikian, $$$A = 30^{\circ}$$$.

Sudut ketiga adalah $$$B = 180^{\circ} - \left(A + C\right)$$$.

Dalam kasus ini, $$$B = 180^{\circ} - \left(30^{\circ} + 60^{\circ}\right) = 90^{\circ}$$$.

Luasnya adalah $$$S = \frac{1}{2} a b \sin{\left(C \right)} = \left(\frac{1}{2}\right)\cdot \left(7\right)\cdot \left(14\right)\cdot \left(\sin{\left(60^{\circ} \right)}\right) = \frac{49 \sqrt{3}}{2}.$$$

Kelilingnya adalah $$$P = a + b + c = 7 + 14 + 7 \sqrt{3} = 7 \left(\sqrt{3} + 3\right)$$$.

$$$a = 7$$$A

$$$b = 14$$$A

$$$c = 7 \sqrt{3}\approx 12.124355652982141$$$A

$$$A = 30^{\circ}$$$A

$$$B = 90^{\circ}$$$A

$$$C = 60^{\circ}$$$A

Luas: $$$S = \frac{49 \sqrt{3}}{2}\approx 42.435244785437494$$$A.

Keliling: $$$P = 7 \left(\sqrt{3} + 3\right)\approx 33.124355652982141$$$A.