Sederhanakan $$$\overline{\left(\overline{A} + B\right) \cdot \left(\overline{B} + C\right)}$$$
Kalkulator terkait: Kalkulator Tabel Kebenaran
Masukan Anda
Sederhanakan ekspresi Boolean $$$\overline{\left(\overline{A} + B\right) \cdot \left(\overline{B} + C\right)}$$$.
Solusi
Terapkan teorema De Morgan $$$\overline{x \cdot y} = \overline{x} + \overline{y}$$$ pada $$$x = \overline{A} + B$$$ dan $$$y = \overline{B} + C$$$:
$${\color{red}\left(\overline{\left(\overline{A} + B\right) \cdot \left(\overline{B} + C\right)}\right)} = {\color{red}\left(\overline{\overline{A} + B} + \overline{\overline{B} + C}\right)}$$Terapkan teorema De Morgan $$$\overline{x + y} = \overline{x} \cdot \overline{y}$$$ pada $$$x = \overline{A}$$$ dan $$$y = B$$$:
$${\color{red}\left(\overline{\overline{A} + B}\right)} + \overline{\overline{B} + C} = {\color{red}\left(\overline{\overline{A}} \cdot \overline{B}\right)} + \overline{\overline{B} + C}$$Terapkan hukum negasi ganda (involusi) $$$\overline{\overline{x}} = x$$$ pada $$$x = A$$$:
$$\left({\color{red}\left(\overline{\overline{A}}\right)} \cdot \overline{B}\right) + \overline{\overline{B} + C} = \left({\color{red}\left(A\right)} \cdot \overline{B}\right) + \overline{\overline{B} + C}$$Terapkan teorema De Morgan $$$\overline{x + y} = \overline{x} \cdot \overline{y}$$$ pada $$$x = \overline{B}$$$ dan $$$y = C$$$:
$$\left(A \cdot \overline{B}\right) + {\color{red}\left(\overline{\overline{B} + C}\right)} = \left(A \cdot \overline{B}\right) + {\color{red}\left(\overline{\overline{B}} \cdot \overline{C}\right)}$$Terapkan hukum negasi ganda (involusi) $$$\overline{\overline{x}} = x$$$ pada $$$x = B$$$:
$$\left(A \cdot \overline{B}\right) + \left({\color{red}\left(\overline{\overline{B}}\right)} \cdot \overline{C}\right) = \left(A \cdot \overline{B}\right) + \left({\color{red}\left(B\right)} \cdot \overline{C}\right)$$Jawaban
$$$\overline{\left(\overline{A} + B\right) \cdot \left(\overline{B} + C\right)} = \left(A \cdot \overline{B}\right) + \left(B \cdot \overline{C}\right)$$$