Integral dari $$$a_{n} i_{n} + b_{n} i_{n} + 1$$$ terhadap $$$x$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \left(a_{n} i_{n} + b_{n} i_{n} + 1\right)\, dx$$$.
Solusi
Terapkan aturan konstanta $$$\int c\, dx = c x$$$ dengan $$$c=a_{n} i_{n} + b_{n} i_{n} + 1$$$:
$${\color{red}{\int{\left(a_{n} i_{n} + b_{n} i_{n} + 1\right)d x}}} = {\color{red}{x \left(a_{n} i_{n} + b_{n} i_{n} + 1\right)}}$$
Oleh karena itu,
$$\int{\left(a_{n} i_{n} + b_{n} i_{n} + 1\right)d x} = x \left(a_{n} i_{n} + b_{n} i_{n} + 1\right)$$
Tambahkan konstanta integrasi:
$$\int{\left(a_{n} i_{n} + b_{n} i_{n} + 1\right)d x} = x \left(a_{n} i_{n} + b_{n} i_{n} + 1\right)+C$$
Jawaban
$$$\int \left(a_{n} i_{n} + b_{n} i_{n} + 1\right)\, dx = x \left(a_{n} i_{n} + b_{n} i_{n} + 1\right) + C$$$A