Calculatrice de dérivées partielles

Calculez les dérivées partielles étape par étape

Cette calculatrice en ligne calculera la dérivée partielle de la fonction, avec les étapes détaillées. Vous pouvez spécifier n'importe quel ordre d'intégration.

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Hint: type x^2,y to calculate `(partial^3 f)/(partial x^2 partial y)`, or enter x,y^2,x to find `(partial^4 f)/(partial x partial y^2 partial x)`.

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Solution

Your input: find $$$\frac{\partial}{\partial z}\left(x^{2} + y^{2} + z^{2} - 14\right)$$$

The derivative of a sum/difference is the sum/difference of derivatives:

$${\color{red}{\frac{\partial}{\partial z}\left(x^{2} + y^{2} + z^{2} - 14\right)}}={\color{red}{\left(- \frac{\partial}{\partial z}\left(14\right) + \frac{\partial}{\partial z}\left(x^{2}\right) + \frac{\partial}{\partial z}\left(y^{2}\right) + \frac{\partial}{\partial z}\left(z^{2}\right)\right)}}$$

Apply the power rule $$$\frac{\partial}{\partial z} \left(z^{n} \right)=n\cdot z^{-1+n}$$$ with $$$n=2$$$:

$${\color{red}{\frac{\partial}{\partial z}\left(z^{2}\right)}} - \frac{\partial}{\partial z}\left(14\right) + \frac{\partial}{\partial z}\left(x^{2}\right) + \frac{\partial}{\partial z}\left(y^{2}\right)={\color{red}{\left(2 z^{-1 + 2}\right)}} - \frac{\partial}{\partial z}\left(14\right) + \frac{\partial}{\partial z}\left(x^{2}\right) + \frac{\partial}{\partial z}\left(y^{2}\right)=2 z - \frac{\partial}{\partial z}\left(14\right) + \frac{\partial}{\partial z}\left(x^{2}\right) + \frac{\partial}{\partial z}\left(y^{2}\right)$$

The derivative of a constant is 0:

$$2 z - {\color{red}{\frac{\partial}{\partial z}\left(14\right)}} + \frac{\partial}{\partial z}\left(x^{2}\right) + \frac{\partial}{\partial z}\left(y^{2}\right)=2 z - {\color{red}{\left(0\right)}} + \frac{\partial}{\partial z}\left(x^{2}\right) + \frac{\partial}{\partial z}\left(y^{2}\right)$$

The derivative of a constant is 0:

$$2 z + {\color{red}{\frac{\partial}{\partial z}\left(x^{2}\right)}} + \frac{\partial}{\partial z}\left(y^{2}\right)=2 z + {\color{red}{\left(0\right)}} + \frac{\partial}{\partial z}\left(y^{2}\right)$$

The derivative of a constant is 0:

$$2 z + {\color{red}{\frac{\partial}{\partial z}\left(y^{2}\right)}}=2 z + {\color{red}{\left(0\right)}}$$

Thus, $$$\frac{\partial}{\partial z}\left(x^{2} + y^{2} + z^{2} - 14\right)=2 z$$$

Answer: $$$\frac{\partial}{\partial z}\left(x^{2} + y^{2} + z^{2} - 14\right)=2 z$$$