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Solution :

Required area = area of the shaded region <br> ` = 2` ( area of the region OBNO ) <br> ` = 2 int _ ( 0 ) ^ ( pi//2) ydx ` , where ` y =sinx ` <br> ` = 2 int _ 0 ^(pi//2) sin x dx ` <br> ` = 2 [ - cos x ] _ 0 ^((pi)/(2)) ` <br> ` = 2 [ - cos ""(pi)/(2) + cos 0] ` <br> ` 2 [ - 0 + 1 ] = 2 ` sq units. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NVT_21_MAT_XII_C15_SLV_002_S01.png" width="80%">