Prime factorization of $$$3873$$$

Find the prime factorization of $$$3873$$$.

Start with the number $$$2$$$.

Determine whether $$$3873$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$3873$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$3873$$$ by $$${\color{green}3}$$$: $$$\frac{3873}{3} = {\color{red}1291}$$$.

The prime number $$${\color{green}1291}$$$ has no other factors then $$$1$$$ and $$${\color{green}1291}$$$: $$$\frac{1291}{1291} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3873 = 3 \cdot 1291$$$.

The prime factorization is $$$3873 = 3 \cdot 1291$$$A.