Prime factorization of $$$892$$$

Find the prime factorization of $$$892$$$.

Start with the number $$$2$$$.

Determine whether $$$892$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$892$$$ by $$${\color{green}2}$$$: $$$\frac{892}{2} = {\color{red}446}$$$.

Determine whether $$$446$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$446$$$ by $$${\color{green}2}$$$: $$$\frac{446}{2} = {\color{red}223}$$$.

The prime number $$${\color{green}223}$$$ has no other factors then $$$1$$$ and $$${\color{green}223}$$$: $$$\frac{223}{223} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$892 = 2^{2} \cdot 223$$$.

The prime factorization is $$$892 = 2^{2} \cdot 223$$$A.