Prime factorization of $$$4708$$$
Your Input
Find the prime factorization of $$$4708$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$4708$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$4708$$$ by $$${\color{green}2}$$$: $$$\frac{4708}{2} = {\color{red}2354}$$$.
Determine whether $$$2354$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$2354$$$ by $$${\color{green}2}$$$: $$$\frac{2354}{2} = {\color{red}1177}$$$.
Determine whether $$$1177$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$1177$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$1177$$$ is divisible by $$$5$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$7$$$.
Determine whether $$$1177$$$ is divisible by $$$7$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$11$$$.
Determine whether $$$1177$$$ is divisible by $$$11$$$.
It is divisible, thus, divide $$$1177$$$ by $$${\color{green}11}$$$: $$$\frac{1177}{11} = {\color{red}107}$$$.
The prime number $$${\color{green}107}$$$ has no other factors then $$$1$$$ and $$${\color{green}107}$$$: $$$\frac{107}{107} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4708 = 2^{2} \cdot 11 \cdot 107$$$.
Answer
The prime factorization is $$$4708 = 2^{2} \cdot 11 \cdot 107$$$A.