Prime factorization of $$$4445$$$
Your Input
Find the prime factorization of $$$4445$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$4445$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$4445$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$4445$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$4445$$$ by $$${\color{green}5}$$$: $$$\frac{4445}{5} = {\color{red}889}$$$.
Determine whether $$$889$$$ is divisible by $$$5$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$7$$$.
Determine whether $$$889$$$ is divisible by $$$7$$$.
It is divisible, thus, divide $$$889$$$ by $$${\color{green}7}$$$: $$$\frac{889}{7} = {\color{red}127}$$$.
The prime number $$${\color{green}127}$$$ has no other factors then $$$1$$$ and $$${\color{green}127}$$$: $$$\frac{127}{127} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4445 = 5 \cdot 7 \cdot 127$$$.
Answer
The prime factorization is $$$4445 = 5 \cdot 7 \cdot 127$$$A.