Prime factorization of $$$4380$$$
Your Input
Find the prime factorization of $$$4380$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$4380$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$4380$$$ by $$${\color{green}2}$$$: $$$\frac{4380}{2} = {\color{red}2190}$$$.
Determine whether $$$2190$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$2190$$$ by $$${\color{green}2}$$$: $$$\frac{2190}{2} = {\color{red}1095}$$$.
Determine whether $$$1095$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$1095$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$1095$$$ by $$${\color{green}3}$$$: $$$\frac{1095}{3} = {\color{red}365}$$$.
Determine whether $$$365$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$365$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$365$$$ by $$${\color{green}5}$$$: $$$\frac{365}{5} = {\color{red}73}$$$.
The prime number $$${\color{green}73}$$$ has no other factors then $$$1$$$ and $$${\color{green}73}$$$: $$$\frac{73}{73} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4380 = 2^{2} \cdot 3 \cdot 5 \cdot 73$$$.
Answer
The prime factorization is $$$4380 = 2^{2} \cdot 3 \cdot 5 \cdot 73$$$A.