Prime factorization of $$$4084$$$

Find the prime factorization of $$$4084$$$.

Start with the number $$$2$$$.

Determine whether $$$4084$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4084$$$ by $$${\color{green}2}$$$: $$$\frac{4084}{2} = {\color{red}2042}$$$.

Determine whether $$$2042$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2042$$$ by $$${\color{green}2}$$$: $$$\frac{2042}{2} = {\color{red}1021}$$$.

The prime number $$${\color{green}1021}$$$ has no other factors then $$$1$$$ and $$${\color{green}1021}$$$: $$$\frac{1021}{1021} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4084 = 2^{2} \cdot 1021$$$.

The prime factorization is $$$4084 = 2^{2} \cdot 1021$$$A.