Prime factorization of $$$3925$$$
Your Input
Find the prime factorization of $$$3925$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$3925$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$3925$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$3925$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$3925$$$ by $$${\color{green}5}$$$: $$$\frac{3925}{5} = {\color{red}785}$$$.
Determine whether $$$785$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$785$$$ by $$${\color{green}5}$$$: $$$\frac{785}{5} = {\color{red}157}$$$.
The prime number $$${\color{green}157}$$$ has no other factors then $$$1$$$ and $$${\color{green}157}$$$: $$$\frac{157}{157} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3925 = 5^{2} \cdot 157$$$.
Answer
The prime factorization is $$$3925 = 5^{2} \cdot 157$$$A.