Prime factorization of $$$3308$$$

Find the prime factorization of $$$3308$$$.

Start with the number $$$2$$$.

Determine whether $$$3308$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$3308$$$ by $$${\color{green}2}$$$: $$$\frac{3308}{2} = {\color{red}1654}$$$.

Determine whether $$$1654$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1654$$$ by $$${\color{green}2}$$$: $$$\frac{1654}{2} = {\color{red}827}$$$.

The prime number $$${\color{green}827}$$$ has no other factors then $$$1$$$ and $$${\color{green}827}$$$: $$$\frac{827}{827} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3308 = 2^{2} \cdot 827$$$.

The prime factorization is $$$3308 = 2^{2} \cdot 827$$$A.