Prime factorization of $$$3272$$$

Find the prime factorization of $$$3272$$$.

Start with the number $$$2$$$.

Determine whether $$$3272$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$3272$$$ by $$${\color{green}2}$$$: $$$\frac{3272}{2} = {\color{red}1636}$$$.

Determine whether $$$1636$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1636$$$ by $$${\color{green}2}$$$: $$$\frac{1636}{2} = {\color{red}818}$$$.

Determine whether $$$818$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$818$$$ by $$${\color{green}2}$$$: $$$\frac{818}{2} = {\color{red}409}$$$.

The prime number $$${\color{green}409}$$$ has no other factors then $$$1$$$ and $$${\color{green}409}$$$: $$$\frac{409}{409} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3272 = 2^{3} \cdot 409$$$.

The prime factorization is $$$3272 = 2^{3} \cdot 409$$$A.