Prime factorization of $$$2636$$$

Find the prime factorization of $$$2636$$$.

Start with the number $$$2$$$.

Determine whether $$$2636$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2636$$$ by $$${\color{green}2}$$$: $$$\frac{2636}{2} = {\color{red}1318}$$$.

Determine whether $$$1318$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1318$$$ by $$${\color{green}2}$$$: $$$\frac{1318}{2} = {\color{red}659}$$$.

The prime number $$${\color{green}659}$$$ has no other factors then $$$1$$$ and $$${\color{green}659}$$$: $$$\frac{659}{659} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2636 = 2^{2} \cdot 659$$$.

The prime factorization is $$$2636 = 2^{2} \cdot 659$$$A.