Prime factorization of $$$2439$$$

Find the prime factorization of $$$2439$$$.

Start with the number $$$2$$$.

Determine whether $$$2439$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$2439$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$2439$$$ by $$${\color{green}3}$$$: $$$\frac{2439}{3} = {\color{red}813}$$$.

Determine whether $$$813$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$813$$$ by $$${\color{green}3}$$$: $$$\frac{813}{3} = {\color{red}271}$$$.

The prime number $$${\color{green}271}$$$ has no other factors then $$$1$$$ and $$${\color{green}271}$$$: $$$\frac{271}{271} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2439 = 3^{2} \cdot 271$$$.

The prime factorization is $$$2439 = 3^{2} \cdot 271$$$A.