Prime factorization of $$$2302$$$

Find the prime factorization of $$$2302$$$.

Start with the number $$$2$$$.

Determine whether $$$2302$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2302$$$ by $$${\color{green}2}$$$: $$$\frac{2302}{2} = {\color{red}1151}$$$.

The prime number $$${\color{green}1151}$$$ has no other factors then $$$1$$$ and $$${\color{green}1151}$$$: $$$\frac{1151}{1151} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2302 = 2 \cdot 1151$$$.

The prime factorization is $$$2302 = 2 \cdot 1151$$$A.