Prime factorization of $$$1432$$$
Your Input
Find the prime factorization of $$$1432$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$1432$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1432$$$ by $$${\color{green}2}$$$: $$$\frac{1432}{2} = {\color{red}716}$$$.
Determine whether $$$716$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$716$$$ by $$${\color{green}2}$$$: $$$\frac{716}{2} = {\color{red}358}$$$.
Determine whether $$$358$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$358$$$ by $$${\color{green}2}$$$: $$$\frac{358}{2} = {\color{red}179}$$$.
The prime number $$${\color{green}179}$$$ has no other factors then $$$1$$$ and $$${\color{green}179}$$$: $$$\frac{179}{179} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1432 = 2^{3} \cdot 179$$$.
Answer
The prime factorization is $$$1432 = 2^{3} \cdot 179$$$A.