Prime factorization of $$$1125$$$
Your Input
Find the prime factorization of $$$1125$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$1125$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$1125$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$1125$$$ by $$${\color{green}3}$$$: $$$\frac{1125}{3} = {\color{red}375}$$$.
Determine whether $$$375$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$375$$$ by $$${\color{green}3}$$$: $$$\frac{375}{3} = {\color{red}125}$$$.
Determine whether $$$125$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$125$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$125$$$ by $$${\color{green}5}$$$: $$$\frac{125}{5} = {\color{red}25}$$$.
Determine whether $$$25$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$25$$$ by $$${\color{green}5}$$$: $$$\frac{25}{5} = {\color{red}5}$$$.
The prime number $$${\color{green}5}$$$ has no other factors then $$$1$$$ and $$${\color{green}5}$$$: $$$\frac{5}{5} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1125 = 3^{2} \cdot 5^{3}$$$.
Answer
The prime factorization is $$$1125 = 3^{2} \cdot 5^{3}$$$A.