$$$\frac{4}{13}\cdot \left\langle 4, -1, -3\right\rangle$$$
Your Input
Calculate $$$\frac{4}{13}\cdot \left\langle 4, -1, -3\right\rangle$$$.
Solution
Multiply each coordinate of the vector by the scalar:
$$${\color{DarkMagenta}\left(\frac{4}{13}\right)}\cdot \left\langle 4, -1, -3\right\rangle = \left\langle {\color{DarkMagenta}\left(\frac{4}{13}\right)}\cdot \left(4\right), {\color{DarkMagenta}\left(\frac{4}{13}\right)}\cdot \left(-1\right), {\color{DarkMagenta}\left(\frac{4}{13}\right)}\cdot \left(-3\right)\right\rangle = \left\langle \frac{16}{13}, - \frac{4}{13}, - \frac{12}{13}\right\rangle$$$
Answer
$$$\frac{4}{13}\cdot \left\langle 4, -1, -3\right\rangle = \left\langle \frac{16}{13}, - \frac{4}{13}, - \frac{12}{13}\right\rangle\approx \left\langle 1.230769230769231, -0.307692307692308, -0.923076923076923\right\rangle$$$A