Magnitude of $$$\left\langle - \frac{75 \cos{\left(5 t \right)}}{17}, - \frac{75 \sin{\left(5 t \right)}}{17}, 0\right\rangle$$$

Find the magnitude (length) of $$$\mathbf{\vec{u}} = \left\langle - \frac{75 \cos{\left(5 t \right)}}{17}, - \frac{75 \sin{\left(5 t \right)}}{17}, 0\right\rangle$$$.

The vector magnitude of a vector is given by the formula $$$\mathbf{\left\lvert\vec{u}\right\rvert} = \sqrt{\sum_{i=1}^{n} \left|{u_{i}}\right|^{2}}$$$.

The sum of squares of the absolute values of the coordinates is $$$\left|{- \frac{75 \cos{\left(5 t \right)}}{17}}\right|^{2} + \left|{- \frac{75 \sin{\left(5 t \right)}}{17}}\right|^{2} + \left|{0}\right|^{2} = \frac{5625 \sin^{2}{\left(5 t \right)}}{289} + \frac{5625 \cos^{2}{\left(5 t \right)}}{289}.$$$

Therefore, the magnitude of the vector is $$$\mathbf{\left\lvert\vec{u}\right\rvert} = \sqrt{\frac{5625 \sin^{2}{\left(5 t \right)}}{289} + \frac{5625 \cos^{2}{\left(5 t \right)}}{289}} = \frac{75}{17}.$$$

The magnitude is $$$\frac{75}{17}\approx 4.411764705882353$$$A.