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Unit vector in the direction of $$$\left\langle 3 \sin^{2}{\left(t \right)} \cos{\left(t \right)}, - 3 \sin{\left(t \right)} \cos^{2}{\left(t \right)}, \sin{\left(2 t \right)}\right\rangle$$$
Your Input
Find the unit vector in the direction of $$$\mathbf{\vec{u}} = \left\langle 3 \sin^{2}{\left(t \right)} \cos{\left(t \right)}, - 3 \sin{\left(t \right)} \cos^{2}{\left(t \right)}, \sin{\left(2 t \right)}\right\rangle.$$$
Solution
The magnitude of the vector is $$$\mathbf{\left\lvert\vec{u}\right\rvert} = \frac{\sqrt{26 - 26 \cos{\left(4 t \right)}}}{4}$$$ (for steps, see magnitude calculator).
The unit vector is obtained by dividing each coordinate of the given vector by the magnitude.
Thus, the unit vector is $$$\mathbf{\vec{e}} = \left\langle \frac{6 \sqrt{26} \sin^{2}{\left(t \right)} \cos{\left(t \right)}}{13 \sqrt{1 - \cos{\left(4 t \right)}}}, - \frac{6 \sqrt{26} \sin{\left(t \right)} \cos^{2}{\left(t \right)}}{13 \sqrt{1 - \cos{\left(4 t \right)}}}, \frac{2 \sqrt{26} \sin{\left(2 t \right)}}{13 \sqrt{1 - \cos{\left(4 t \right)}}}\right\rangle$$$ (for steps, see vector scalar multiplication calculator).
Answer
The unit vector in the direction of $$$\left\langle 3 \sin^{2}{\left(t \right)} \cos{\left(t \right)}, - 3 \sin{\left(t \right)} \cos^{2}{\left(t \right)}, \sin{\left(2 t \right)}\right\rangle$$$A is $$$\left\langle \frac{6 \sqrt{26} \sin^{2}{\left(t \right)} \cos{\left(t \right)}}{13 \sqrt{1 - \cos{\left(4 t \right)}}}, - \frac{6 \sqrt{26} \sin{\left(t \right)} \cos^{2}{\left(t \right)}}{13 \sqrt{1 - \cos{\left(4 t \right)}}}, \frac{2 \sqrt{26} \sin{\left(2 t \right)}}{13 \sqrt{1 - \cos{\left(4 t \right)}}}\right\rangle\approx \left\langle \frac{2.353393621658208 \sin^{2}{\left(t \right)} \cos{\left(t \right)}}{\left(1 - \cos{\left(4 t \right)}\right)^{0.5}}, - \frac{2.353393621658208 \sin{\left(t \right)} \cos^{2}{\left(t \right)}}{\left(1 - \cos{\left(4 t \right)}\right)^{0.5}}, \frac{0.784464540552736 \sin{\left(2 t \right)}}{\left(1 - \cos{\left(4 t \right)}\right)^{0.5}}\right\rangle.$$$A