RREF of $$$\left[\begin{array}{cc}7 & 24\\0 & 1\end{array}\right]$$$
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Your Input
Find the reduced row echelon form of $$$\left[\begin{array}{cc}7 & 24\\0 & 1\end{array}\right]$$$.
Solution
Divide row $$$1$$$ by $$$7$$$: $$$R_{1} = \frac{R_{1}}{7}$$$.
$$$\left[\begin{array}{cc}1 & \frac{24}{7}\\0 & 1\end{array}\right]$$$
Subtract row $$$2$$$ multiplied by $$$\frac{24}{7}$$$ from row $$$1$$$: $$$R_{1} = R_{1} - \frac{24 R_{2}}{7}$$$.
$$$\left[\begin{array}{cc}1 & 0\\0 & 1\end{array}\right]$$$
Answer
The reduced row echelon form is $$$\left[\begin{array}{cc}1 & 0\\0 & 1\end{array}\right]$$$A.
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