RREF of $$$\left[\begin{array}{cccc}\frac{5}{2} & 120 & \frac{6}{5} & \frac{37}{10}\\5 & 240 & \frac{12}{5} & \frac{37}{5}\\3 & 180 & \frac{9}{5} & \frac{11}{2}\end{array}\right]$$$
Related calculators: Gauss-Jordan Elimination Calculator, Matrix Inverse Calculator
Your Input
Find the reduced row echelon form of $$$\left[\begin{array}{cccc}\frac{5}{2} & 120 & \frac{6}{5} & \frac{37}{10}\\5 & 240 & \frac{12}{5} & \frac{37}{5}\\3 & 180 & \frac{9}{5} & \frac{11}{2}\end{array}\right]$$$.
Solution
Multiply row $$$1$$$ by $$$\frac{2}{5}$$$: $$$R_{1} = \frac{2 R_{1}}{5}$$$.
$$$\left[\begin{array}{cccc}1 & 48 & \frac{12}{25} & \frac{37}{25}\\5 & 240 & \frac{12}{5} & \frac{37}{5}\\3 & 180 & \frac{9}{5} & \frac{11}{2}\end{array}\right]$$$
Subtract row $$$1$$$ multiplied by $$$5$$$ from row $$$2$$$: $$$R_{2} = R_{2} - 5 R_{1}$$$.
$$$\left[\begin{array}{cccc}1 & 48 & \frac{12}{25} & \frac{37}{25}\\0 & 0 & 0 & 0\\3 & 180 & \frac{9}{5} & \frac{11}{2}\end{array}\right]$$$
Subtract row $$$1$$$ multiplied by $$$3$$$ from row $$$3$$$: $$$R_{3} = R_{3} - 3 R_{1}$$$.
$$$\left[\begin{array}{cccc}1 & 48 & \frac{12}{25} & \frac{37}{25}\\0 & 0 & 0 & 0\\0 & 36 & \frac{9}{25} & \frac{53}{50}\end{array}\right]$$$
Since the element at row $$$2$$$ and column $$$2$$$ (pivot element) equals $$$0$$$, we need to swap the rows.
Find the first nonzero element in column $$$2$$$ under the pivot entry.
The first nonzero element is at row $$$3$$$.
Swap the rows $$$2$$$ and $$$3$$$:
$$$\left[\begin{array}{cccc}1 & 48 & \frac{12}{25} & \frac{37}{25}\\0 & 36 & \frac{9}{25} & \frac{53}{50}\\0 & 0 & 0 & 0\end{array}\right]$$$
Divide row $$$2$$$ by $$$36$$$: $$$R_{2} = \frac{R_{2}}{36}$$$.
$$$\left[\begin{array}{cccc}1 & 48 & \frac{12}{25} & \frac{37}{25}\\0 & 1 & \frac{1}{100} & \frac{53}{1800}\\0 & 0 & 0 & 0\end{array}\right]$$$
Subtract row $$$2$$$ multiplied by $$$48$$$ from row $$$1$$$: $$$R_{1} = R_{1} - 48 R_{2}$$$.
$$$\left[\begin{array}{cccc}1 & 0 & 0 & \frac{1}{15}\\0 & 1 & \frac{1}{100} & \frac{53}{1800}\\0 & 0 & 0 & 0\end{array}\right]$$$
Since the element at row $$$3$$$ and column $$$3$$$ (pivot element) equals $$$0$$$, we need to swap the rows.
Find the first nonzero element in column $$$3$$$ under the pivot entry.
As can be seen, there are no such entries. Move to the next column.
Since the element at row $$$3$$$ and column $$$4$$$ (pivot element) equals $$$0$$$, we need to swap the rows.
Find the first nonzero element in column $$$4$$$ under the pivot entry.
As can be seen, there are no such entries.
Answer
The reduced row echelon form is $$$\left[\begin{array}{cccc}1 & 0 & 0 & \frac{1}{15}\\0 & 1 & \frac{1}{100} & \frac{53}{1800}\\0 & 0 & 0 & 0\end{array}\right]\approx \left[\begin{array}{cccc}1 & 0 & 0 & 0.066666666666667\\0 & 1 & 0.01 & 0.029444444444444\\0 & 0 & 0 & 0\end{array}\right].$$$A