REF of $$$\left[\begin{array}{ccc}1 & 2 & 3\\2 & 5 & 7\\4 & 9 & 13\end{array}\right]$$$

Find the row echelon form of $$$\left[\begin{array}{ccc}1 & 2 & 3\\2 & 5 & 7\\4 & 9 & 13\end{array}\right]$$$.

Subtract row $$$1$$$ multiplied by $$$2$$$ from row $$$2$$$: $$$R_{2} = R_{2} - 2 R_{1}$$$.

$$$\left[\begin{array}{ccc}1 & 2 & 3\\0 & 1 & 1\\4 & 9 & 13\end{array}\right]$$$

Subtract row $$$1$$$ multiplied by $$$4$$$ from row $$$3$$$: $$$R_{3} = R_{3} - 4 R_{1}$$$.

$$$\left[\begin{array}{ccc}1 & 2 & 3\\0 & 1 & 1\\0 & 1 & 1\end{array}\right]$$$

Subtract row $$$2$$$ from row $$$3$$$: $$$R_{3} = R_{3} - R_{2}$$$.

$$$\left[\begin{array}{ccc}1 & 2 & 3\\0 & 1 & 1\\0 & 0 & 0\end{array}\right]$$$

Since the element at row $$$3$$$ and column $$$3$$$ (pivot element) equals $$$0$$$, we need to swap the rows.

Find the first nonzero element in column $$$3$$$ under the pivot entry.

As can be seen, there are no such entries.

The row echelon form is $$$\left[\begin{array}{ccc}1 & 2 & 3\\0 & 1 & 1\\0 & 0 & 0\end{array}\right]$$$A.