$$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\\1 & 2 & 3\end{array}\right]\cdot \left[\begin{array}{ccc}- \frac{1}{2} & 0 & \frac{1}{2}\\5 & -1 & -1\\- \frac{7}{2} & 1 & \frac{1}{2}\end{array}\right]$$$

Calculate $$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\\1 & 2 & 3\end{array}\right]\cdot \left[\begin{array}{ccc}- \frac{1}{2} & 0 & \frac{1}{2}\\5 & -1 & -1\\- \frac{7}{2} & 1 & \frac{1}{2}\end{array}\right].$$$

$$$\left[\begin{array}{ccc}{\color{Blue}4} & {\color{Green}5} & {\color{BlueViolet}7}\\{\color{GoldenRod}2} & {\color{DeepPink}1} & {\color{Brown}0}\\{\color{Peru}1} & {\color{DarkBlue}2} & {\color{Crimson}3}\end{array}\right]\cdot \left[\begin{array}{ccc}{\color{Fuchsia}- \frac{1}{2}} & {\color{Purple}0} & {\color{Chartreuse}\frac{1}{2}}\\{\color{BlueViolet}5} & {\color{DarkMagenta}-1} & {\color{DarkBlue}-1}\\{\color{Magenta}- \frac{7}{2}} & {\color{SaddleBrown}1} & {\color{Chocolate}\frac{1}{2}}\end{array}\right] = \left[\begin{array}{ccc}{\color{Blue}\left(4\right)}\cdot {\color{Fuchsia}\left(- \frac{1}{2}\right)} + {\color{Green}\left(5\right)}\cdot {\color{BlueViolet}\left(5\right)} + {\color{BlueViolet}\left(7\right)}\cdot {\color{Magenta}\left(- \frac{7}{2}\right)} & {\color{Blue}\left(4\right)}\cdot {\color{Purple}\left(0\right)} + {\color{Green}\left(5\right)}\cdot {\color{DarkMagenta}\left(-1\right)} + {\color{BlueViolet}\left(7\right)}\cdot {\color{SaddleBrown}\left(1\right)} & {\color{Blue}\left(4\right)}\cdot {\color{Chartreuse}\left(\frac{1}{2}\right)} + {\color{Green}\left(5\right)}\cdot {\color{DarkBlue}\left(-1\right)} + {\color{BlueViolet}\left(7\right)}\cdot {\color{Chocolate}\left(\frac{1}{2}\right)}\\{\color{GoldenRod}\left(2\right)}\cdot {\color{Fuchsia}\left(- \frac{1}{2}\right)} + {\color{DeepPink}\left(1\right)}\cdot {\color{BlueViolet}\left(5\right)} + {\color{Brown}\left(0\right)}\cdot {\color{Magenta}\left(- \frac{7}{2}\right)} & {\color{GoldenRod}\left(2\right)}\cdot {\color{Purple}\left(0\right)} + {\color{DeepPink}\left(1\right)}\cdot {\color{DarkMagenta}\left(-1\right)} + {\color{Brown}\left(0\right)}\cdot {\color{SaddleBrown}\left(1\right)} & {\color{GoldenRod}\left(2\right)}\cdot {\color{Chartreuse}\left(\frac{1}{2}\right)} + {\color{DeepPink}\left(1\right)}\cdot {\color{DarkBlue}\left(-1\right)} + {\color{Brown}\left(0\right)}\cdot {\color{Chocolate}\left(\frac{1}{2}\right)}\\{\color{Peru}\left(1\right)}\cdot {\color{Fuchsia}\left(- \frac{1}{2}\right)} + {\color{DarkBlue}\left(2\right)}\cdot {\color{BlueViolet}\left(5\right)} + {\color{Crimson}\left(3\right)}\cdot {\color{Magenta}\left(- \frac{7}{2}\right)} & {\color{Peru}\left(1\right)}\cdot {\color{Purple}\left(0\right)} + {\color{DarkBlue}\left(2\right)}\cdot {\color{DarkMagenta}\left(-1\right)} + {\color{Crimson}\left(3\right)}\cdot {\color{SaddleBrown}\left(1\right)} & {\color{Peru}\left(1\right)}\cdot {\color{Chartreuse}\left(\frac{1}{2}\right)} + {\color{DarkBlue}\left(2\right)}\cdot {\color{DarkBlue}\left(-1\right)} + {\color{Crimson}\left(3\right)}\cdot {\color{Chocolate}\left(\frac{1}{2}\right)}\end{array}\right] = \left[\begin{array}{ccc}- \frac{3}{2} & 2 & \frac{1}{2}\\4 & -1 & 0\\-1 & 1 & 0\end{array}\right]$$$

$$$\left[\begin{array}{ccc}4 & 5 & 7\\2 & 1 & 0\\1 & 2 & 3\end{array}\right]\cdot \left[\begin{array}{ccc}- \frac{1}{2} & 0 & \frac{1}{2}\\5 & -1 & -1\\- \frac{7}{2} & 1 & \frac{1}{2}\end{array}\right] = \left[\begin{array}{ccc}- \frac{3}{2} & 2 & \frac{1}{2}\\4 & -1 & 0\\-1 & 1 & 0\end{array}\right] = \left[\begin{array}{ccc}-1.5 & 2 & 0.5\\4 & -1 & 0\\-1 & 1 & 0\end{array}\right]$$$A