Determinant of $$$\left[\begin{array}{cc}8 - \lambda & 12\\12 & 26 - \lambda\end{array}\right]$$$
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Your Input
Calculate $$$\left|\begin{array}{cc}8 - \lambda & 12\\12 & 26 - \lambda\end{array}\right|$$$.
Solution
The determinant of a 2x2 matrix is $$$\left|\begin{array}{cc}a & b\\c & d\end{array}\right| = a d - b c$$$.
$$$\left|\begin{array}{cc}8 - \lambda & 12\\12 & 26 - \lambda\end{array}\right| = \left(8 - \lambda\right)\cdot \left(26 - \lambda\right) - \left(12\right)\cdot \left(12\right) = \lambda^{2} - 34 \lambda + 64$$$
Answer
$$$\left|\begin{array}{cc}8 - \lambda & 12\\12 & 26 - \lambda\end{array}\right| = \left(\lambda - 32\right) \left(\lambda - 2\right)$$$A
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