Determinant of $$$\left[\begin{array}{cc}- \frac{6}{t^{2}} & 0\\\frac{12}{t^{3}} & 0\end{array}\right]$$$
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Your Input
Calculate $$$\left|\begin{array}{cc}- \frac{6}{t^{2}} & 0\\\frac{12}{t^{3}} & 0\end{array}\right|$$$.
Solution
Since column $$$2$$$ consists solely of zeros, the determinant of the matrix equals $$$0$$$.
Answer
$$$\left|\begin{array}{cc}- \frac{6}{t^{2}} & 0\\\frac{12}{t^{3}} & 0\end{array}\right| = 0$$$A
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