Intercepts of $$$\left(x + 4\right)^{2} + \left(y - 3\right)^{2} = 4$$$
Your Input
Find find the x- and y-intercepts of $$$\left(x + 4\right)^{2} + \left(y - 3\right)^{2} = 4$$$.
Solution
To find the x-intercepts, substitute $$$y = 0$$$ into the equation and solve the resulting equation $$$\left(x + 4\right)^{2} + 9 = 4$$$ for $$$x$$$ (use the equation solver).
To find the y-intercepts, substitute $$$x = 0$$$ into the equation and solve the resulting equation $$$\left(y - 3\right)^{2} + 16 = 4$$$ for $$$y$$$ (use the equation solver).
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