Synthetic Division Calculator
Perform synthetic division step by step
The calculator will divide the polynomial by the binomial using synthetic division, with steps shown.
Related calculator: Polynomial Long Division Calculator
Solution
Your input: find $$$\frac{2 x^{3} + x^{2} - 13 x + 6}{x + 1}$$$ using synthetic division.
Write the problem in a division-like format.
To do this:
- Take the constant term of the divisor with the opposite sign and write it to the left.
- Write the coefficients of the dividend to the right.
$$$\begin{array}{c|cccc}&x^{3}&x^{2}&x^{1}&x^{0}\\-1&2&1&-13&6\\&&\\\hline&\end{array}$$$
Step 1
Write down the first coefficient without changes:
$$$\begin{array}{c|rrrr}-1&\color{Chocolate}{2}&1&-13&6\\&&\\\hline&\color{Chocolate}{2}\end{array}$$$
Step 2
Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).
Add the obtained result to the next coefficient of the dividend, and write down the sum.
$$$\begin{array}{c|rrrr}\color{Magenta}{-1}&2&\color{Blue}{1}&-13&6\\&&\left(\color{Magenta}{-1}\right) \cdot \color{Chocolate}{2}=\color{Red}{-2}\\\hline&\color{Chocolate}{2}&\color{Blue}{1}+\left(\color{Red}{-2}\right)=\color{Green}{-1}\end{array}$$$
Step 3
Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).
Add the obtained result to the next coefficient of the dividend, and write down the sum.
$$$\begin{array}{c|rrrr}\color{Magenta}{-1}&2&1&\color{BlueViolet}{-13}&6\\&&-2&\left(\color{Magenta}{-1}\right) \cdot \left(\color{Blue}{-1}\right)=\color{Red}{1}\\\hline&2&\color{Blue}{-1}&\left(\color{BlueViolet}{-13}\right)+\color{Red}{1}=\color{Green}{-12}\end{array}$$$
Step 4
Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).
Add the obtained result to the next coefficient of the dividend, and write down the sum.
$$$\begin{array}{c|rrrr}\color{Magenta}{-1}&2&1&-13&\color{GoldenRod}{6}\\&&-2&1&\left(\color{Magenta}{-1}\right) \cdot \left(\color{BlueViolet}{-12}\right)=\color{Red}{12}\\\hline&2&-1&\color{BlueViolet}{-12}&\color{GoldenRod}{6}+\color{Red}{12}=\color{Green}{18}\end{array}$$$
We have completed the table and have obtained the following resulting coefficients: $$$2, -1, -12, 18$$$.
All the coefficients except the last one are the coefficients of the quotient, the last coefficient is the remainder.
Thus, the quotient is $$$2 x^{2}- x-12$$$, and the remainder is $$$18$$$.
Therefore, $$$\frac{2 x^{3} + x^{2} - 13 x + 6}{x + 1}=2 x^{2} - x - 12+\frac{18}{x + 1}$$$
Answer: $$$\frac{2 x^{3} + x^{2} - 13 x + 6}{x + 1}=2 x^{2} - x - 12+\frac{18}{x + 1}$$$