Discriminant of $$$\frac{5 x^{2}}{128} - x - 9 = 0$$$

Find the discriminant of $$$\frac{5 x^{2}}{128} - x - 9 = 0$$$.

The discriminant of the quadratic equation $$$a x^{2} + b x + c = 0$$$ is $$$D = b^{2} - 4 a c$$$.

Our equation is $$$\frac{5 x^{2}}{128} - x - 9 = 0$$$, so $$$a = \frac{5}{128}$$$, $$$b = -1$$$, $$$c = -9$$$.

Thus, $$$D = \left(-1\right)^{2} - \left(4\right)\cdot \left(\frac{5}{128}\right)\cdot \left(-9\right) = \frac{77}{32}$$$.

The discriminant of $$$\frac{5 x^{2}}{128} - x - 9 = 0$$$A is $$$\frac{77}{32} = 2.40625$$$A.